python – 解析DeepDiff结果

local =  [{1: {'age': 50, 'name': 'foo'}}, {2: {'age': 90, 'name': 'bar'}}, {3: {'age': 60, 'name': 'foobar'}}]
online = [{1: {'age': 50, 'name': 'foo'}}, {2: {'age': 40, 'name': 'bar'}}]
ddiff = DeepDiff(local, online)
added, updated = ddiff['iterable_item_added'], ddiff['values_changed']
added = {'root[2]': {3: {'age': 60, 'name': 'foobar'}}}
updated = {"root[1][2]['age']": {'new_value': 90, 'old_value': 40}}

现在,我想采取：

list_indexes_added = foo(added)
list_indexes_updated = foo(updated)

并获得：

list_indexes_added = [2]
list_index_updated = [(1,2,'age')]

通过这种方式,我可以操作本地和在线列表,并在将来更新在线表.

我正在考虑正则表达式,但也许还有其他选择.

from ast import literal_eval
import re


def str_diff_parse(str_diff):
    return [tuple(literal_eval(y) for y in re.findall(r"\[('?\w+'?)\]", x)) for x in str_diff]

added = {'root[2]': {3: {'age': 60, 'name': 'foobar'}}}
updated = {"root[1][2]['age']": {'new_value': 90, 'old_value': 40}}

list_indexes_added = str_diff_parse(added)
list_indexes_updated = str_diff_parse(updated)

print(list_indexes_added)
print(list_indexes_updated)
# prints
#[(2,)]
#[(1, 2, 'age')]

演示：http://ideone.com/3MhTky

>还会推荐dictdiffer模块,它将diff作为可消耗的python diff对象返回,可以将其修补到原始字典以获取更新的字典,反之亦然.