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我需要创建一个for循环,该循环会在每次检测到不存在的键时生成一个新的嵌套字典.我正在从以前的函数中获取外部字典的信息.
>它将需要创建一个字典,以可用的运动作为其键,并以字典作为其
值.
>在内部词典中,运动员名称将用作其键和奖牌数
(整数)将为其值.
键=运动,价值= {：}
CSE 231春季2019
>该函数将从get_country_stats()的字典中循环查找
运动员,运动和奖牌.请注意,当您想为一项新运动添加一名运动员时,您需要
首先为该运动创建一个空字典,然后再向其添加运动员.
>奖章的类型(金,银,铜)与我们的新词典无关,它们都是
视为1枚勋章.
我启动了两个空字典,外字典和内字典.然后创建一个外部for循环,该循环遍历所有键值对并返回一个列表
def display_best_athletes_per_sport(Athlete, Country, Sports):
medals = 0
outer_dict = {}
inner_dict = {}
for key, value in Country.items():
for item in value:
athlete = item[0]
medals = item[5]
sport = item[3]
inner_dict = {athlete:medals}
outer_dict = {sport:inner_dict}
if sport not in outer_dict:
new_dict[sport] = value[i]
if medals in value:
medals += 1
else:
medals = 1
如果找不到所需的键(运动),我希望能够生成新的外部词典,每次为特定运动员找到奖牌时,都要更新内部词典的值.
这是Country函数的输出,该函数正在即时尝试中使用：
{'FIN': [
('Juhamatti Tapio Aaltonen', 'Finland', 2014, 'ice hockey', "ice hockey men's ice hockey", 'bronze'),
('Paavo Johannes Aaltonen', 'Finland', 1948, 'gymnastics', "gymnastics men's individual all-around", 'bronze'),
('Paavo Johannes Aaltonen', 'Finland', 1948, 'gymnastics', "gymnastics men's team all-around", 'gold'),
('Paavo Johannes Aaltonen', 'Finland', 1948, 'gymnastics', "gymnastics men's horse vault", 'gold'),
('Paavo Johannes Aaltonen', 'Finland', 1948, 'gymnastics', "gymnastics men's pommelled horse", 'gold'),
('Paavo Johannes Aaltonen', 'Finland', 1952, 'gymnastics', "gymnastics men's team all-around", 'bronze')],
'NOR': [
('Kjetil Andr Aamodt', 'Norway', 1992, 'alpine skiing', "alpine skiing men's super g", 'gold'),
('Kjetil Andr Aamodt', 'Norway', 1992, 'alpine skiing', "alpine skiing men's giant slalom", 'bronze'),
('Kjetil Andr Aamodt', 'Norway', 1994, 'alpine skiing', "alpine skiing men's downhill", 'silver'),
('Kjetil Andr Aamodt', 'Norway', 1994, 'alpine skiing', "alpine skiing men's super g", 'bronze'),
('Kjetil Andr Aamodt', 'Norway', 1994, 'alpine skiing', "alpine skiing men's combined", 'silver'),
('Kjetil Andr Aamodt', 'Norway', 2002, 'alpine skiing', "alpine skiing men's super g", 'gold'),
('Kjetil Andr Aamodt', 'Norway', 2002, 'alpine skiing', "alpine skiing men's combined", 'gold'),
('Kjetil Andr Aamodt', 'Norway', 2006, 'alpine skiing', "alpine skiing men's super g", 'gold'),
('Ann Kristin Aarnes', 'Norway', 1996, 'football', "football women's football", 'bronze')],
'NED': [('Pepijn Aardewijn', 'Netherlands', 1996, 'rowing', "rowing men's lightweight double sculls", 'silver')]}
最佳答案
好吧,这只猫现在已经出了书.所以这是我的看法.我认为将检查条目显示在dict中与将某些内容添加到该条目分开是很好的.因此,当您添加条目时,它始终“尚无任何内容”.这样,无论条目是否存在,都可以用相同的方式对待“将下一项添加到条目”.鉴于此,正如我所看到的,这是您想要做什么的基本概念：
def display_best_athletes_per_sport(Athlete, Country, Sports):
outer_dict = {}
for key, value in Country.items():
for item in value:
athlete = item[0]
medals = item[5]
sport = item[3]
if sport not in outer_dict:
outer_dict[sport] = {}
if athlete not in outer_dict[sport]:
outer_dict[sport][athlete] = 0
outer_dict[sport][athlete] += 1
pprint(outer_dict)
结果如下：
{'alpine skiing': {'Kjetil Andr Aamodt': 8},
'football': {'Ann Kristin Aarnes': 1},
'gymnastics': {'Paavo Johannes Aaltonen': 5},
'ice hockey': {'Juhamatti Tapio Aaltonen': 1},
'rowing': {'Pepijn Aardewijn': 1}}
这与@gmds提供的答案相同,因此两者都是解决问题的有效方法,并且处理方法非常相似.
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